The reverse recovery time of a diode is t_rr = 3 μs and the rate of fall of the diode current is \(\frac{{di}}{{dt}} = 30\;A/\mu s\). The storage charge Q_RR and the peak inverse current I_RR will be respectively

135 μC and 90 A

270 μC and 90 A

270 μC and 60 A

135 μC and 60 A

Question Not Attempted

The reverse recovery time of a diode is trr = 3 μs and the rate of fall of the diode current is \(\frac{{di}}{{dt}} = 30\;A/\mu s\). The storage charge QRR and the peak inverse current IRR will be respectively