Which one is one of the factors of

\({x^2} + \frac{1}{{{x^2}}} + 8\left( {x + \frac{1}{x}} \right) + 14\)

1
\(x + \frac{1}{x} + 1\)
2
\(x + \frac{1}{x} + 3\)
3
\(x + \frac{1}{x} + 6\)
4
\(x + \frac{1}{x} + 7\)

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