If \(3x+6y+9z = \dfrac{20}{3}, 6x+9y + 3z = \dfrac{17}{3}\) and \(18x+ 27y - z = \dfrac{113}{9}\), then what is the value of \(75x+113y \ ?\)

1
163/3
2
143/6
3
218/9
4
311/3

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