Simplify the expression:
\(\frac{1}{8}\)\(\left[\frac{1}{b-1}-\frac{1}{b+1}-\frac{2}{b^2+1}-\frac{4}{b^4+1}\right] \)
1
\(\frac{1}{b^8-1}\)
2
\(\frac{8}{b^8+1} \)
3
\(\frac{8}{b^8-1} \)
4
\(\frac{1}{b^8+1}\)
Simplify the expression:
\(\frac{1}{8}\)\(\left[\frac{1}{b-1}-\frac{1}{b+1}-\frac{2}{b^2+1}-\frac{4}{b^4+1}\right] \)