If the diameter of a solid steel bar is to be designed for torque T, then the permissible shear stress is considered as:
1
\(\frac{\text { Ultimate stress }}{\text { Factor of safety }}\)
2
\(\frac{\text { Ultimate stress }}{(2 \times \text { Factor of safety) }}\)
3
\(\frac{\text { Yield stress }}{(2 \times \text { Factor of safety })}\)
4
\(\frac{\text { Yield stress }}{\text { Factor of safety }}\)