Let ‘L’ be the inductance of the system, ‘C’ be the capacitance of the system, ‘I’ be the instantaneous value of are current, and ‘V’ be the instantaneous value of capacitor voltage, which appears across the breaker when it opens. The prospective voltage or arc voltage is determined as:
1
\(V = I /{\sqrt {{L}{C}}}\)
2
\(V = I\;\sqrt {\frac{L}{C}}\)
3
\(V = I {\sqrt {{L}{C}}}\)
4
\(V = I\;\sqrt {\frac{C}{L}}\)
5
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