The solution of the equation \(\frac {dy}{dx} = e^{x + y} + x^2e^y\) is

1
\(e^{x - y} + \frac {x^3} 3 + c\)
2
\(e^{x} + e^{-y} + \frac {x^3} 3 = c\)
3
\(e^{x} - e^{-y} = \frac {x^3} 3 + c\)
4
None

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