The distance between the parallel planes 3x + y + 3z = 8 and 9x + 3y + 9z = 15 is:

1
\(\frac{5}{{\sqrt 19}}\)
2
\(\frac{7}{{\sqrt 19}}\)
3
\(\frac{3}{{\sqrt 19}}\)
4
\(\frac{9}{{\sqrt 19}}\)

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