\(\int e^{x}\left[\frac{x^{2}+1}{(x+1)^{2}}\right] d x\) is equal to

1
\(-\frac{e^{x}}{x+1}+C\)
2
\(e^{x}\left(\frac{x-1}{x+1}\right)+C\)
3
\(\frac{e^{x}}{x+1}+C\)
4
\(\frac{x e^{x}}{x+1}+C\)

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