If \(y = e^{tan^{-1}x}\), then \((1+x^2)\frac{d^2y}{dx^2}\) is equal to

1
\(x\frac{dy}{dx}\)
2
\((1-2x)\frac{dy}{dx}\)
3
\((2x-1)\frac{dy}{dx}\)
4
(1 - 2x)y

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