The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is

1
\(\frac{h}{K^2_{G}+h^2}\)
2
\(\frac{K^2_{G}+h^2}{h}\)
3
\(\frac{h^2}{K^2_{G}+h^2}\)
4
\(\frac{K^2_{G}+h^2}{h^2}\)
5
Question Not Attempted

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