In a flat belt drive, the maximum tension which the belt can be subjected to is T and the mass of the belt per unit length is m kg. The velocity of the belt for maximum power transmission is
1
\(\sqrt{\frac{T}{3m}}\)
2
\(\sqrt{\frac{T}{m}}\)
3
\(\frac{T}{3m}\)
4
\(\frac{T}{m}\)
5
Question Not Attempted