A child is standing at the centre of a turntable with his arms stretched then the table is rotating about its central axis with angular speed ω0. Now the child folds his arms the moment of Inertia of the child becomes \(\frac{1}{3}\) of its initial value. Then the angular speed of the turntable will be:

1
3ω0
2
\(\frac{1}{3}ω_0\) 
3
6ω0
4
\(\frac{1}{6}ω_0\)

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