Let α, β, γ, δ ∈ Z and let A (α, β), B (1, 0), C (γ, δ) and D (1, 2) be the vertices of a parallelogram ABCD. If AB = \(\sqrt {10}\) and the points A and C lie on the line 3y = 2x + 1, then 2 (α + β + γ + δ) is equal to

1
10
2
5
3
12
4
8

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