\(\tan \left[\frac{\pi}{4}+\frac{1}{2} \cos ^{-1} \frac{a}{b}\right] \) + \(\tan \left[\frac{\pi}{4}-\frac{1}{2} \cos ^{-1} \frac{a}{b}\right]\) is equal to

1
\(\frac{2 a}{b}\)
2
\(\frac{2 b}{a}\)
3
\(\frac{a}{b}\)
4
\(\frac{b}{a}\)

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