Let \(A\) and \(B\) be two invertible matrices of order \(3 \times 3\). If det \((ABA^T)=8\) and det \((AB^{-1})=8\), then det \((BA^{-1}\,B^T)\) is equal to:

1
\(16\)
2
\(\dfrac{1}{16}\)
3
\(\dfrac{1}{4}\)
4
\(1\)

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