The general solution of cotθ + tanθ  = 2 is

1
\(\rm \theta=\frac{n\pi}{2}+(-1)^n \frac{\pi}{8}\)
2
\(\rm \theta=\frac{n\pi}{2}+(-1)^n \frac{\pi}{6}\)
3
\(\rm \theta=\frac{n\pi}{2}+(-1)^n \frac{\pi}{4}\)
4
\(\rm \theta=n\pi+(-1)^n \frac{\pi}{8}\)

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