Let \( \alpha=\frac{(4!)!}{(4!)^{3!}}\ and \ \beta=\frac{(5!)!}{(5!)^{4!}}\). Then:

1
\( \alpha \in \mathrm{N}\) and \( \beta \notin \mathrm{N}\)
2
\( \alpha \notin \mathrm{N}\) and  \( \beta \in \mathrm{N}\)
3
\(\alpha \in \mathrm{N}\) and \( \beta \in \mathrm{N}\)
4
\( \alpha \notin \mathrm{N}\) and \( \beta \notin \mathrm{N}\)

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