\(\int {{e^{ - 2x}}} \sin 3x\,dx = \)

1
\(\frac{1}{{13}}{e^{ - 2x}}[\sin 3x + \cos 3x] + c\)
2
\(-\frac{1}{{13}}{e^{ - 2x}}[\sin 3x + \cos 3x] + c\)
3
\(\frac{1}{{13}}{e^{ - 2x}}[2 sin 3x + 3x\cos 3x] + c\)
4
\(-\frac{1}{{13}}{e^{ - 2x}}[2\sin 3x + 3\cos 3x] + c\)

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