If two different numbers are taken from the set \(\{0,1, 2, 3, ......, 10\}\); then the probability that their sum as well as absolute difference are both multiple of \(4\), is.
1
\(\displaystyle\frac{6}{55}\)
2
\(\displaystyle\frac{12}{55}\)
3
\(\displaystyle\frac{14}{45}\)
4
\(\displaystyle\frac{7}{55}\)