Let A(2, 3 ,5) and C(-3, 4,-2) be opposite vertices of a parallelogram ABCD if the diagonal \(\overrightarrow{B D}=\hat{i}+2 \hat{j}+3 \hat{k}\) then the area of the parallelogram is equal to
1
\(\frac{1}{2} \sqrt{410}\)
2
\(\frac{1}{2} \sqrt{474}\)
3
\(\frac{1}{2} \sqrt{586}\)
4
\(\frac{1}{2} \sqrt{306}\)