Let \(\rm \frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), a > b be an ellipse, whose eccentricity is \(\rm \frac{1}{\sqrt2}\) and the length of the latus rectum is \(\sqrt{14}\). Then the square of the eccentricity of \(\rm \frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) is :
1
3
2
7/2
3
3/2
4
5/2