If \(\frac{x}{b + c -a } = \frac{y}{b - c - a} = \frac{z }{a + b -c} = k\) then what is x2 + y2 + z2 - 2xy - 2yz + 2zx equal to ?

1
k2(a2 + b2 + c2)
2
k2(a2 - b2 + c2)
3
k2(a + b + c)2
4
k2(a - b + c)2

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