If x and y are two numbers having opposite signs, and x2 ∶ y2 = 16 ∶ 81, then what is the value of \(\frac{3x+4y}{2x-3y}?\)

1
\(\frac{48}{35}\)
2
\(-\frac{27}{40}\)
3
\(-\frac{24}{35}\)
4
\(\frac{12}{25}\)

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