In a constituency, 55% of the total number of voters are males and the rest are females. If 40% of the males are illiterate and 40% of the females are literate, then by what percent is the number of literate males more than that of illiterate females?
1
\(18\frac{2}{9}\)
2
\(22\frac{8}{{11}}\)
3
\(22\frac{2}{9}\)
4
\(18\frac{2}{{11}}\)