Quantitative Aptitude Trigonometry

In a right ΔABC with right angle at ∠ABC. If AC = 2√5 and AB - BC = 2, then sec A + tan A is

1
\(\sqrt5\over2\)
2
2√5
3
\(\frac{\sqrt5+1}{2}\)
4
\(1\over\sqrt5\)

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