defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Three Dimensional Geometry Equation of a Line
The image of the line \(\dfrac{x-1}{3}=\dfrac{y-3}{1}=\dfrac{z-4}{-5}\) in the plane \(2x-y+z+3=0\) is the line
1
\(\dfrac{x+3}{3}=\dfrac{y-5}{1}=\dfrac{z-2}{-5}\)
2
\(\dfrac{x+3}{-3}=\dfrac{y-5}{-1}=\dfrac{z+2}{5}\)
3
\(\dfrac{x-3}{3}=\dfrac{y+5}{1}=\dfrac{z-2}{-5}\)
4
\(\dfrac{x-3}{-3}=\dfrac{y+5}{-1}=\dfrac{z-2}{5}\)