defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Sequences and Series Special Series
For any n ∈ N, \(\frac{1}{2.5}+\frac{1}{5.8}+\ldots+\frac{1}{(3 n−1)(3 n+2)}\) =
1
\(\frac{n}{6n+4}\)
2
\(\frac{n^{2}}{6n+4}\)
3
\(\frac{1}{2}.\frac{n^{2}}{6n+4}\)
4
\(\frac{n}{6n^{2}+4}\)