If logx3y2 = a and \(\log \frac{x}{y} = b\), then \(\frac{\log x}{\log y}\) is equal to

1
\(\frac{a \ - \ 3b}{a \ + \ 2b}\)
2
\(\frac{a \ + \ 3b}{a \ - \ 2b}\)
3
\(\frac{a \ + \ 2b}{a \ - \ 2b}\)
4
\(\frac{a \ + \ 2b}{a \ - \ 3b}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation