The distance of the line \(\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}\) from the point (1, 4, 0) along the line \(\frac{x}{1}=\frac{y-2}{2}=\frac{z+3}{3}\) is:

1
\(\sqrt{17}\)
2
\(\sqrt{14}\)
3
\(\sqrt{15}\)
4
\(\sqrt{13}\)

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