A ball of mass m = 1 Kg is thrown from the top of a building with initial velocity \(\overrightarrow{v}\) = (20 m/s) \(\widehat{i}\) + (24 m/s) \(\widehat{j}\) at time t = 0 s. The change in the potential energy of the ball between t = 0 and t = 6s, if the ball does not hit the ground (Assume g = 10 m/s2)

1
-320 J
2
-360 J
3
-380 J
4
+320 J

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