If the Earth has no rotational motion, the weight of a person on the equator is W. Determine the speed with which the earth would have to rotate about its axis so that the person at the equator will weigh \(\frac{3}{4}\) W. radius of the Earth is 6400 km and g = 10 \(m/s^2\).
1
\(1.1 \times10^{-3} \, \text{rad/s}\)
2
\(0.63 \times10^{-3} \, \text{rad/s}\)
3
\(0.28 \times10^{-3} \, \text{rad/s}\)
4
\(0.83 \times10^{-3} \, \text{rad/s}\)