defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Integral Calculus Definite Integrals
For 0 < a < 1, the value of the integral \( \int_0^\pi \frac{d x}{1-2 a \cos x+a^2}\) is:
1
\( \frac{\pi^2}{\pi+a^2}\)
2
\( \frac{\pi^2}{\pi-a^2}\)
3
\( \frac{\pi}{1-a^2}\)
4
\( \frac{\pi}{1+a^2} \)