defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Trigonometry Trigonometric Ratios
If √3cos2θ + 2sin2θ = \(\frac{sin^2θ (sec^2θ + 1)}{sec^2θ -1}\), 0° < θ > 90° , then find the value of tan2θ.
1
√3 + 1
2
2 + √3
3
2 - √3
4
1 - √3