defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Integral Calculus Definite Integrals
Let \(\rm \displaystyle \int_\alpha^{\log _e 4} \frac{{dx}}{\sqrt{{e}^{{x}}-1}}=\frac{\pi}{6}\). Then eα and e-α are the roots of the equation :
1
2x2 – 5x + 2 = 0
2
x2 – 2x - 8 = 0
3
2x2 – 5x – 2 = 0
4
x2 + 2x – 8 = 0