The area of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is

1
\(​\frac{3}{8}\) sq units
2
\(​\frac{5}{8}\) sq units
3
\(​\frac{7}{8}\) sq units
4
\(​\frac{9}{8}\) sq units

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