Let f : \(\mathbb{R}\) - {0} → \(\mathbb{R}\) be a function satisfying \(f\left(\frac{x}{y}\right)=\frac{f(x)}{f(y)}\) for all x, y, f(y) ≠ 0. If f' (1) = 2024, then

1
xf' (x) - 2024 f(x) = 0
2
xf' (x) + 2024f(x) = 0
3
xf' (x) + f(x) = 2024
4
xf' (x) - 2023f(x) = 0

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