If \(\overrightarrow{AC}=2\hat{i}+\hat{j}+\hat{k}\) and \(\overrightarrow{BD}=-\hat{i}+3\hat{j}+2\hat{k}\) then the area of the quadrilateral ABCD is

1
\(\dfrac{5}{2}\sqrt{3}\)
2
\(5\sqrt{3}\)
3
\(\dfrac{15}{2}\sqrt{3}\)
4
\(10\sqrt{3}\)

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