If \(\vec a = 4\hat i + 6 \hat j\) and \(\vec b = 3 \hat j + 4 \hat k\) then the vector component of \(\vec a\) along \(\vec b\) is
1
\(\frac{{18}}{{10\sqrt 3 }}(3j + 4k)\)
2
\(\frac{{18}}{{25}}(3j + 4k)\)
3
\(\frac{{18}}{{\sqrt 3 }}(3j + 4k)\)
4
(3j + 4k)