defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Three Dimensional Geometry Angle with Planes
The equation of the line through the point (0, 1, 2) and perpendicular to the line \(\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{-2}\) is :
1
\(\frac{x}{3} = \frac{y - 1}{4} = \frac{z - 2}{-3}\)
2
\(\frac{x}{-3} = \frac{y - 1}{4} = \frac{z - 2}{3}\)
3
\(\frac{x}{3} = \frac{y - 1}{-4} = \frac{z - 2}{3}\)
4
\(\frac{x}{3} = \frac{y - 1}{4} = \frac{z - 2}{3}\)