defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Integral Calculus Definite Integrals
If \(I_{n}=\int_{0}^{\frac{\pi}{4}} \tan ^{n} x d x\), for n ≥ 2, then \(I_{n}+I_{n-2}=\)
1
\(\frac{1}{n-1}\)
2
\(\frac{1}{n+1}\)
3
\(\frac{1}{n}+\frac{1}{n-2}\)
4
\(\frac{1}{n}\)