If A, B and (adj(A–1) + adj(B–1)) are non-singular matrices of same order, then the inverse of A(adj(A–1) + adj(B–1))–1B, is equal to

1
AB–1 + A–1B
2
adj(B–1) + adj(A–1)  
3
\(\frac{1}{|\mathrm{AB}|}\)(adj(B) +adj(A))
4
\(\frac{\mathrm{AB}^{-1}}{|\mathrm{~A}|}+\frac{\mathrm{BA}^{-1}}{|\mathrm{~B}|}\)

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