If \(\dfrac{(x+2)!}{(2x-1)!}\times\dfrac{(2x+1)!}{(x+3)!}=\dfrac{72}{7}\), where x ∈ N then find the value of x?

1
\(\dfrac{-54}{28}\)
2
4
3
-4
4
\(\dfrac{54}{28}\)

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