The mean square value of the random variable X whose probability density function (PDF) is given below, will be?
\(P\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{K}{4}\left( {x + 1} \right)\; - 1 \le x \le 3}\\ {0\;\;\;\;\;\;otherwise} \end{array}} \right., \ K = \frac{1}{2}\)
1
11/3
2
3/11
3
1/2
4
None