If \(\rm f(x)=\frac{4x+3}{6x-4}, x \ne \frac{2}{3}\) and (fof) (x) = g(x), where g: ℝ - \(\rm \left\{\frac{2}{3}\right\}\) → ℝ - \(\rm \left\{\frac{2}{3}\right\}\), then (gogog) (4) is equal to

1
\(-\frac{19}{20}\)
2
\(\frac{19}{20}\)
3
-4
4
4

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