If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is :

1
\(\frac{33}{2^{32}}\)
2
\(\frac{33}{2^{29}}\)
3
\(\frac{33}{2^{28}}\)
4
\(\frac{33}{2^{27}}\)

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