Three numbers are chosen at random without replacement from the set A = {x ∈ Z | 2 ≤ x ≤ 11}. The probability that the minimum of choosen numbers is 3 and maximum is 7 is

1
\(\frac{1}{30}\)
2
\(\frac{1}{40}\)
3
\(\frac{1}{50}\)
4
\(\frac{1}{60}\)

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