Quantitative Aptitude Geometry Triangles

If Δ ABC ~ Δ QRP, \(\rm \frac{ar(\Delta ABC)}{ar(PQR)}=\frac{9}{4}\), AB = 18 cm and BC = 15 cm, then PR is equal to:

1
8 cm
2
\(\frac{21}{4}\) cm
3
10 cm
4
12 cm

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Other Tools: chatwiz.hivanix.in mmspace.hivanix.in unogame.hivanix.in

Quick Navigation

Home

Subjects

Chapters