Light of wavelength λA and λB falls on two identical metal plates A and B respectively. The maximum kinetic energy of photoelectrons is KA and KB respectively, then which one of the following relations is true (λA = 2λB)

1
\(\mathrm{K}_{\mathrm{A}}<\frac{\mathrm{K}_{\mathrm{B}}}{2}\)
2
2KA = KB
3
KA = 2KB
4
KA > 2KB

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