A long straight conductor is bent into shape as shown. If it carries \(1\;A\) and its radius is R, then magnetic field B at the centre of circular coil

1
\(\infty\)
2
Zero
3
\(\dfrac{\mu_0l(\pi+1)}{2\pi R}\)
4
\(\dfrac{\mu_0l(\pi-1)}{2\pi R}\)

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